HackerRank String validators problem solution in python | python problem solution

Python has built-in string validation methods for basic data. It can check if a string is composed of alphabetical characters, alphanumeric characters, digits, etc.

str.isalnum()
This method checks if all the characters of a string are alphanumeric (a-z, A-Z and 0-9).

>>> print 'ab123'.isalnum()
True
>>> print 'ab123#'.isalnum()
False

---

str.isalpha()
This method checks if all the characters of a string are alphabetical (a-z and A-Z).

>>> print 'abcD'.isalpha()
True
>>> print 'abcd1'.isalpha()
False

---

str.isdigit()
This method checks if all the characters of a string are digits (0-9).

>>> print '1234'.isdigit()
True
>>> print '123edsd'.isdigit()
False

---

str.islower()
This method checks if all the characters of a string are lowercase characters (a-z).

>>> print 'abcd123#'.islower()
True
>>> print 'Abcd123#'.islower()
False

---

str.isupper()
This method checks if all the characters of a string are uppercase characters (A-Z).

>>> print 'ABCD123#'.isupper()
True
>>> print 'Abcd123#'.isupper()
False

---

Task

You are given a string .
Your task is to find out if the string  contains: alphanumeric characters, alphabetical characters, digits, lowercase and uppercase characters.

A single line containing a string .

Constraints

In the first line, print True if  has any alphanumeric characters. Otherwise, print False.
In the second line, print True if  has any alphabetical characters. Otherwise, print False.
In the third line, print True if  has any digits. Otherwise, print False.
In the fourth line, print True if  has any lowercase characters. Otherwise, print False.
In the fifth line, print True if  has any uppercase characters. Otherwise, print False.

qA2

True
True
True
True
True

Problem solution in Python 2 programming.
S = raw_input()
print True if any(k in "0123456789" or k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k.lower() in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k in "0123456789" for k in S) else False
print True if any(k in "abcdefghijklmnopqrstuvwxyz" for k in S) else False
print True if any(k in "ABCDEFGHIJKLMNOPQRSTUVWXYZ" for k in S) else False

Problem solution in Python 3 programming.
if __name__ == '__main__':
    s = input()
    print(any(a.isalnum() for a in s) )
    print(any(a.isalpha() for a in s) )
    print(any(a.isdigit() for a in s) )
    print(any(a.islower() for a in s) )
    print(any(a.isupper() for a in s) )

Problem solution in pypy programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT
S=raw_input()
a=0
for i in range(len(S)):
    if S[i].isalnum():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'

a=0
for i in range(len(S)):
    if S[i].isalpha():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'
    
a=0
for i in range(len(S)):
    if S[i].isdigit():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'
    
a=0
for i in range(len(S)):
    if S[i].islower():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'
    
a=0
for i in range(len(S)):
    if S[i].isupper():
         a+=1
if a>0:
    print 'True'
else:
    print 'False'


Problem solution in pypy3 programming.
if __name__ == '__main__':
    s = input()
    print(any(c.isalnum() for c in s))
    print(any(c.isalpha() for c in s))
    print(any(c.isdigit() for c in s))
    print(any(c.islower() for c in s))
    print(any(c.isupper() for c in s))