HackerRank Finding the percentage solution in python | hacker rank interview Question solution
Table of Contents
The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.
Example
The query_name is ‘beta’. beta’s average score is .
Input Format
The first line contains the integer , the number of students’ records. The next lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.
Constraints
Output Format
Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.
Sample Input 0
3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika
Sample Output 0
56.00
Explanation 0
Marks for Malika are whose average is
Sample Input 1
2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh
Sample Output 1
26.50
In this HackerRank Finding the percentage problem solution in python, we need to develop a python program that can read a dictionary that contains the key-value pairs of name and marks list of students. and we need to print the average of marks of every student on the output screen.
Problem solution in Python 2 programming.
n=int(raw_input())
dic={}
for i in range(n):
line=raw_input().split()
dic[line[0]]=sum(map(float,line[1:]))/3.0
print '%.2f' % dic[raw_input()]Problem solution in Python 3 programming.
if __name__ == '__main__':
n = int(input())
student_marks = {}
for _ in range(n):
name, *line = input().split()
scores = list(map(float, line))
student_marks[name] = scores
query_name = input()
if query_name in student_marks:
x = ((float(student_marks[query_name][0]) + float(student_marks[query_name][1]) + float(student_marks[query_name][2])) / 3)
print('%.2f' % x)Problem solution in pypy programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT
d={}
for _ in range(int(raw_input())):
item = raw_input().split()
name = item[0]
grade = [float(a) for a in item[1:]]
d[name] = grade
request = raw_input().strip()
avg = reduce(lambda x, y: x + y, d[request])/len(d[request])
print '%.2f' %(avg)Problem solution in pypy3 programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT
n = int(input())
c = 1
students = {}
while c <= n :
line = input()
inList = line.split()
students[inList[0]] = inList[1:4]
c += 1
student = input()
sum = 0
for gs in students[student]:
sum = sum + float(gs)
print('{0:.2f}'.format(sum / 3))
