Table of Contents
Given an integer, , print the following values for each integer from to :
- Decimal
- Octal
- Hexadecimal (capitalized)
- Binary
Function Description
Complete the print_formatted function in the editor below.
print_formatted has the following parameters:
- int number: the maximum value to print
Prints
The four values must be printed on a single line in the order specified above for each from to . Each value should be space-padded to match the width of the binary value of and the values should be separated by a single space.
Input Format
A single integer denoting .
Constraints
Sample Input
17
Sample Output
1 1 1 1
2 2 2 10
3 3 3 11
4 4 4 100
5 5 5 101
6 6 6 110
7 7 7 111
8 10 8 1000
9 11 9 1001
10 12 A 1010
11 13 B 1011
12 14 C 1100
13 15 D 1101
14 16 E 1110
15 17 F 1111
16 20 10 10000
17 21 11 10001
In this HackerRank String Formatting problem in python we need to code a program in which we can accept an integer input n that's greater than 1. and on the output screen, we need to print out the binary, decimal, hexadecimal and octal number of that given integer.
Problem solution in Python 2 programming.
N = int(raw_input())
width = len(str(bin(N)))-2
for num in range(1,N+1):
for base in 'doXb':
print '{0:{width}{base}}'.format(num, base=base, width=width),Problem solution in Python 3 programming.
N = int(input())
l = len(bin(N)) - 2
for i in range(1, N + 1):
f = ""
for c in "doXb":
if f:
f += " "
f += "{:>" + str(l) + c + "}"
print(f.format(i, i, i, i))Problem solution in PyPy programming.
n = int(raw_input())
width = len("{0:b}".format(n))
for i in xrange(1,n+1):
print "{0:{width}d} {0:{width}o} {0:{width}X} {0:{width}b}".format(i, width=width)Problem solution in pypy3 programming.
def print_formatted(number):
width=len(bin(number))-2
for num in range(1,number+1):
for base in ('d', 'o', 'X', 'b'):
print("{0:{width}{base}}".format(num, base=base, width=width), end=' ')
print()