HackerRank Finding the percentage solution in python | hacker rank interview Question solution

August 4, 2022 blogTech

Table of Contents

The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

Example

The query_name is ‘beta’. beta’s average score is .

Input Format

The first line contains the integer , the number of students’ records. The next lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.

Constraints

Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Sample Input 0

3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika

Sample Output 0

56.00

Explanation 0

Marks for Malika are whose average is

Sample Input 1

2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh

Sample Output 1

26.50

In this HackerRank Finding the percentage problem solution in python, we need to develop a python program that can read a dictionary that contains the key-value pairs of name and marks list of students. and we need to print the average of marks of every student on the output screen.

Problem solution in Python 2 programming.
n=int(raw_input())

dic={}

for i in range(n):
	line=raw_input().split()
	dic[line[0]]=sum(map(float,line[1:]))/3.0

print '%.2f' % dic[raw_input()]

Problem solution in Python 3 programming.
if __name__ == '__main__':
    n = int(input())
    student_marks = {}
    for _ in range(n):
        name, *line = input().split()
        scores = list(map(float, line))
        student_marks[name] = scores
    query_name = input()

    if query_name in student_marks:
        x = ((float(student_marks[query_name][0]) + float(student_marks[query_name][1]) + float(student_marks[query_name][2])) / 3)
    
    print('%.2f' % x)

Problem solution in pypy programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT
d={}
for _ in range(int(raw_input())):
    item = raw_input().split()
    name = item[0]
    grade = [float(a) for a in item[1:]]  
    d[name] = grade
request = raw_input().strip()

avg = reduce(lambda x, y: x + y, d[request])/len(d[request])
print '%.2f' %(avg)

Problem solution in pypy3 programming.
# Enter your code here. Read input from STDIN. Print output to STDOUT

n = int(input())

c = 1
students = {}
while c <= n :
    line = input()
    inList = line.split()
    students[inList[0]] = inList[1:4]
    c += 1
    
student = input()

sum = 0
for gs in students[student]:
    sum = sum + float(gs)

print('{0:.2f}'.format(sum / 3))